Home
Class 12
PHYSICS
A granite rod of 60 cm length is clamped...

A granite rod of 60 cm length is clamped at its middle point and is set into longitudinal vibrations. The densit of grantite is `2.7 xx 10^(3) kg// m^(3)` and its Young's modulus is `9.27 xx 10^(10) ` Pa. WHat will be the fundamental frequency of the longitudinal vibrations?

A

10 kHz

B

7.5 kHz

C

5 kHz

D

2.5 kHz

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

A steel rod 100 cm long is clamped at its middle. The fundamental frequency of longitudinal vibrations of the rod is given to be 2.53k Hz. What is the speed of sound in steel?

The diameter of a brass rod is 4 mm and Young's modulus of brass is 9 xx 10^(10) N//m^(2) . The force required to stretch by 0.1 % of its length is

The strain energy per unit volume is 6.25 xx lO^-4 J/m^3 .The young’s Modulus of the wire is 2 xx 10^10 N//m^2 . Calculate strain.

The momentum of a photon is 3.3xx10^(-29) kg-m/s. Its frequency will be

Calculate the value of acceleration due to gravity on the surface of Mars if the radius of Mars = 3.4 xx 10^3 km and its mass is 6.4 xx 10^23 kg.

The moment if inertia of the earth about its axis of rotation is 9.83 xx 10^37 kgm^2 and if its angular velocity is 7.3 xx 10^-5 rad s^-1 . Calculate Kinetic Energy of rotation.

The moment if inertia of the earth about its axis of rotation is 9.83 xx 10^37 kgm^2 and if its angular velocity is 7.3 xx 10^-5 rad s^-1 . Calculate Radius of gyration

At 127^(@)C radiated energy is 2.7 xx 10^(-3) J//s . At what temperature radiated energy is 4.32 xx 10^(6) J//s