Home
Class 12
PHYSICS
A body having a surface area of 50cm^2 r...

A body having a surface area of `50cm^2` radiates 300J of energy per minute at a temperature of `727^(@)C`. The emissivity of the body is
( Stefan's constant`=5.67xx10^(-8)W//m^2K^4`)

A

0.09

B

0.018

C

0.36

D

0.54

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A body having surface area 5 cm^2 and temperature of 727^@C radiates 300 J of energy per minutes. What is its emissivity?(Stefan's constanta sigma=5.7xx10^-8 J//mk^4 )

A body of surface area 10 cm^2 and temperature 727^@C emits 300 J of energy per minutes.Find the emissivity.

A body of surface are 15xx10^(-3)m^2 emits 0.3 kcal in 40 second at a temperature 70^(@)C . The emissive power of the surface at that temperature is

A spherical black body of 5 cm radius is maintained at a temperature of 327^@C . Then the power radiated will be ( sigma = 5.7 xx 10^(-8) SI unit )

The surface of a black body is at a temperature 727^(@)C and its cross section is 1m^(2) Heat radiated from this surface in one minute in Joules is (Stefan's constant =5.7 xx 10^(-8) W//m^(2)//k^(4)) .

Assuming that the sun radiates as a black body, calculate the energy radiated per minute by unit area of its surface. Surface temperature of the sun = 5727^@C and Stefan's constant = 5.7 xx10^-8 Jm^-2K^-4s^-1 .

A copper sphere has a surface area of 3.142 xx 10^-2m^2 and its emissivity is 0.018. Find the energy lost by the sphere per second when its temperature is 100^@C . ( sigma = 5.67 xx 10^-8 W/m^2k^4 .)

Find the surface area of black body maintained at 127^@C radiating energy at the rate of 1459.2 J//sec .

Calculate the energy radiated in 30 seconds by perfectly black sphere of radius5cm maintained at 127^@C . (Stefan's constant s = 5.7 xx 10^-8 J//m^2sk^4)