Home
Class 12
PHYSICS
A liquid in a beaker has temperature the...

A liquid in a beaker has temperature `theta(t)` at time t and `theta_0` is temperature of surroundings, then according to Newton's law of cooling the correct graph between `log_e (theta-theta_0)` and t is

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The graph between surface tension and temperature T is

A body cools in a surrounding which is at a constant temperature of theta_0 .Assume that it obeys Newton's law of cooling. Its temperature theta is plotted against time t. Tangents are drawn to the curve at the points P(theta=theta_1) and Q(theta=theta_2) . These tangents meet the time axis at angles of 0/_2 and 0/_1 as shown

A body cools from a temperature 3 T to 2 T in 10 minutes. The room temperature is T . Assume that Newton's law of cooling is applicable. The temperature of the body at the end of next 10 minutes will be

If a piece of metal is heated to temperature and then allowed to cool in a room which is at temperature theta_0 , the graph between the temperature T of the metal and time I will be closest to :

A solid sphere and a hollow sphere of the same material and size are heated to the same temperature and allowed to cool in the same surroundings. If the temperature difference between each sphere and its surroundings is T then

Chose the correct option int_0^(pi//2) sin theta d theta is equal to

Consider two hot bodies B_(1) and B_(2) which have temperature 100^(@)"C" and 80^(@)"C" respectively at t = 0. The temperature of surroundings is 40^(@)" C" . The ratio of the respective rates of cooling R_(1) and R_(2) of these two bodies at t = 0 will be

In an experiment of Newton's law or cooling the graph between the rate of cooling of the body and excess of temperature with the surrounding is ______

If sintheta=(2t)/(1+t^2) and theta lies in 2nd quadrant ,then costheta is equal to