Home
Class 12
PHYSICS
Potentiometer wire of length 1 m is conn...

Potentiometer wire of length `1 m` is connected in series with `490 Omega` resistance and `2 V` battery. If `0.2 mV / cm` is the potential gradient, then resistance of the potentiameter wire is approximately

A

`4.9Omega`

B

`7.9Omega`

C

`5.9Omega`

D

`6.9Omega`

Text Solution

Verified by Experts

Promotional Banner

Similar Questions

Explore conceptually related problems

A 2 volt battery, a 15 Omega resistor and a potentiometer of 100 cm length, all are connected in series. If the resistance resistance of potentiometer wire is 5 Omega , then the potential gradient of the potentiometer wire is

A potentiometer wire has a length of 2m and resistance 10Omega . It is connected in series with resistance 990Omega and a cell of emf 2V. Calculate the potential gradient along the wire.

A potentiometer wire of length 100 cm has a resistance of 10Omega . It is connected in series with a resistance and an accumulator of e.m.f. 2 V and negligible internal resistance. A source of e.m.f. 10 mV is balanced against a 40 cm length of the potentiometer wire. The value of the external resistance is

A potentiometer wire of length 1m and resistance 10 Omega is connected in series with a cell of emf 2V with internal resistance 1 Omega and a resistance box including a resistance R. If potential difference between the ends of the wire is 1 mV, the value of R is

A potentiometer wire of length 10 m is connected in series with a battery the emf of a cell balances against 250 cm length of wire if length of potentiometer wire is increased by 1 m then new balancing length of wire will be

A potentiometer wire of Length L and a resistance r are connected in series with a battery of e.m.f. E_(0) and a resistance r_(1) . An unknown e.m.f. E is balanced at a length l of the potentiometer wire. The e.m.f. E will be given by :

A potentiometer wire has length 4 m and resistance 8Ω. The resistance that must be connected in series with the wire and an accumulator of e.m.f. 2 V, so as to get a potential gradient 1 mV per cm on the wire is

A potentiometer wire of length 4 m and resistance 8 Omega is connected in, series with a battery of e.m.f. 2 V and negligible internal resistance. If the e.m.f. of cell balances against length of 217 cm of the wire, find the e.m.f. of cell. When the cell is shunted by assistance of 15 Omega ,the balancing length is reduced to 200 cm. Find the internal resistance of the cell

A potentiometer consists of a wire of length 4 m and resistance 10 Omega . If is connected of cell of emf 2V . The potential difference per unit length of the wire will be

A potentiometer wire of length 10 m and resistance 9 ohm is connected to a battery of e.m.f. 2.1 volt having internal resistance 1.5 Omega . Find the potential gradient along the wire and the balancing length for a cell of e.m.f. 1.08 volt .