Home
Class 12
PHYSICS
The coil of galvanometer consists of 80 ...

The coil of galvanometer consists of 80 turns and effective area of 5 `cm^(2)`. The restoring couple is `10^(-8)` Nm//radian. The magnetic field between the pole pieces is 5 T. The current sensitivity of this galvanometer is

A

`5 xx 10^(4) "rad/"muA`

B

`5 xx 10^(-6) "rad/A"`

C

`2 xx 10^(7)"rad/A"`

D

`20 "rad/"muA`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

A moving coil galvanometer has 28 turns and area of coil is 4 xx 10^(-2) m^(2) .If the magnetic field is 0.2 T, then to increase the current sensitivity by 25% without changing area and field, the number of turns should be changed to

A circular coil of 500 turns and area of 0.5 cm^2 carries a current of 10 A. The magnetic moment associated with it_______.

A galvanometer of resistance 95 Omega shunted by a resistance of 5 Omega gives deflection of 50 divisions when joined in series with resistance of 20 k Omega and 2.0 V accumulator. The current sensitivity of the galvanometer in division per mu A is

A moving coil galvanometer has been fitted with a rectangular coil having 50 turns and dimensions 5 cmi xx 3 cm . The radial magnetic field in which the coil is suspended is of 0.05 wb//m^2 . The torsional constant of the spring is 1.5 xx 10^-9 Nm//degree . Obtain the current required to be passed through the galvanometer so as to produce a deflation of 30^@ .

A rectangular coil of 25 turns, area of 25 cm^2 and resistance of 4 ohm//turn is placed perpendicular to a varying magnetic field, which changes at the rate of 500 T//s . The induced current in the coil is

A flat circular coil of 70 turns and radius 10 cm carriers a current I. If the magnetic field at the centre of the coil is 0.003 wb//m^2 , find the value of current.

A square coil of side 10 cm consists of 20 turns and carries a current of 12A. The coil is suspended vertically and the normal to the plane of the coil makes an angle of 30^@ with the direction of a uniform horizontal magnetic field 0.8 T. What is the magnitude of torque experienced by the coil?

The strength of the magnetic field along solenoid having 5000 turns per meter is 3.14 xx 10^-2 T . The current flowing through the solenoid is