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In a ammeter 0.2% of main current passes...

In a ammeter `0.2%` of main current passes through the galvanometer. If resistance of galvanometer is `G`, the resistance of ammeter will be

A

`(1)/(499)`G

B

`(499)/(500)`G

C

`(1)/(500)`G

D

`(500)/(499)`G

Text Solution

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The correct Answer is:
C
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