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The enthalpy of formation of ammonia gas...

The enthalpy of formation of ammonia gas at 298 K is -46.11 kJ `mol^(-1)`. The equation to which this value relates is

A

`1/2 N_(2(g))+3/2 H_(2(g))to NH_(3(g))`

B

`N_((g))+3H_((g))to NH_(3(g))`

C

`N_(2(g))+3 H_(2(g))to 2 NH_(3(g))`

D

`1/2 N_(2(g))+3/2 H_(2(g))to NH_(3(l))`

Text Solution

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The correct Answer is:
A
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