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X=3YZ^(2) find dimension of Y in (MKSA) ...

`X=3YZ^(2)` find dimension of `Y` in (MKSA) system, if `X` and `Z` are the dimension of capacity and magnetic field respectively

A

`[M^(-3)L^(-2)T^(-4)A^(-1)]`

B

`[M^(1)L^(-2)]`

C

`[M^(-3)L^(-2)T^(4)A^(4)]`

D

`[M^(-3)L^(-2)T^(8)A^(4)]`

Text Solution

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The correct Answer is:
d
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