Home
Class 11
PHYSICS
The radius of a sphere is (5.3 +- 0.1)cm...

The radius of a sphere is `(5.3 +- 0.1)`cm` The percentage error in its volume is

A

`3 + 6.01 xx (100)/(5.3)`

B

`(1)/(3) xx 0.01 xx(100)/(5.3)`

C

`((3 xx 0.1)/(5.3)) xx 100`

D

` (0.1)/(5.3) xx 100`

Text Solution

Verified by Experts

The correct Answer is:
c
Promotional Banner

Topper's Solved these Questions

  • MEASUREMENTS

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING ( MISCELLANEOUS)|6 Videos

  • MEASUREMENTS

    TARGET PUBLICATION|Exercise EVALUATION TEST|17 Videos

  • MEASUREMENTS

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING ( DIMENSIONAL ANALYSIS)|43 Videos

  • MAGNETISM

    TARGET PUBLICATION|Exercise MCQs|147 Videos

  • Motion in a plane

    TARGET PUBLICATION|Exercise Exercise|340 Videos

Similar Questions

Explore conceptually related problems

The error in measurement of radius of a sphere is 0.1% then error in its volume is -

The radius of a sphere measured is 4.68 ± 0.01 cm. Estimate the percentage error in the measurement of the volume of the sphere.

Assertion: The error in the measurement of radius of sphere is 0.3% . The permissible error in its surface area is 0.6 % . Reason: The permissible error is calculated by the formula (Delta A)/(A) = (4 Delta r)/( r) .

The percentage error in the measurment of mass of a body is 0.75% and the percenatage error in the measurement of its speed is 1.85%. Then the percentage error in the measurement of its kinetic energy is

The side of an object measured by means of a vernier callipers is 3.52 cm. If the least count of the vernier is 0.01 cm,estimate the percentage error in the measurement.

The least count of a screw gauge is 0.005 cm . The diameter of wire is 0.02 cm as measured by it. The percentage error in measurement is

The radius of a solid sphere is 40 cm. The radius of gyration when the axis of rotation is along a tangent in a plane in cm is

The volume of a solid cylinder of length 10 cm and radius 4 cm is measured using a vernier calliper which has a least count 0.01 cm. Find the percentage error in the measurement.

The surface area of a sphere increases at the rate of 0.6cm^2 /sec. The rate at which its volume is increasing when its radius is 10cm, is...... A) 12 cc/sec B) 3 cc/sec C) 4 cc/sec D) 5 cc/sec

TARGET PUBLICATION-MEASUREMENTS-COMPETITIVE THINKING (ACCURAY AND ERRORS IN MEASUREMENTS)
  1. Choose the INCOREET statement out of the folloiwng .

    Text Solution

    |

  2. Assertion: The error in the measurement of radius of sphere is 0.3%. T...

    Text Solution

    |

  3. If Y = a-b, the maximum percentage error in the measurement of Y will ...

    Text Solution

    |

  4. The radius of a sphere is (5.3 +- 0.1)cm The percentage error in its v...

    Text Solution

    |

  5. Resistance of a given wire is obtained by measuring the current flowin...

    Text Solution

    |

  6. In an experiment four quantities a,b,c and d are measure with percenta...

    Text Solution

    |

  7. Let x={:[(a^(2)b^(2))/(c)]:} be the physical quantity. If the percenta...

    Text Solution

    |

  8. Two full turns of the circular scale of a screw gauge cover a distanc...

    Text Solution

    |

  9. A screw gauge with a pitch of 0.5mm and a circular scale with 50 divis...

    Text Solution

    |

  10. A student measured the diameter of a small steel ball using a screw ga...

    Text Solution

    |

  11. The density of a solid ball is to be determined in an experiment. The ...

    Text Solution

    |

  12. A force vecF applied on a square plate of length L. If the percent...

    Text Solution

    |

  13. The density of a material in the shape of a cube is determined by meas...

    Text Solution

    |

  14. In the determination if Young's modulus ((Y = (4MLg)/(pild^(2)) by usi...

    Text Solution

    |

  15. If the time period of a simple pendulum is T = 2pi sqrt(l//g) , t...

    Text Solution

    |

  16. A student measures the value of g with the help of a simple pendulu...

    Text Solution

    |

  17. The period of oscillation of a simple pendulum is T = 2pisqrt((L)/(g))...

    Text Solution

    |

  18. The following observations were taken for dtermining the surface tensi...

    Text Solution

    |