A screw gauge with a pitch of `0.5mm` and a circular scale with `50` divisions is used to measure the thickness of a thin sheet of Aluminum. Before starting the measurement, it is found that wen the jaws of the screw gauge are brought in c0ntact, the `45^(th)` division coincide with the main scale line and the zero of the main scale is barely visible. what is the thickness of the sheet if the main scale readind is `0.5 mm` and the `25th` division coincide with the main scale line?

Options

A. 0.80 cm
B. 0.70 cm
C. 0.50 cm
D. 0.75 cm

Answer

a