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The potential energy of a particle varie...

The potential energy of a particle varies with distance `x` from a fixed origin as `U = (A sqrt(x))/( x^(2) + B)`, where `A and B` are dimensional constants , then find the dimensional formula for `AB`.

A

`[M^(1)L^(7//2)T^(-2)]`

B

`[M^(1)L^(11//2)T^(-2)]`

C

`[M^(1)L^(5//2)T^(-2)]`

D

`[M^(1)L^(9//2)T^(-2)]`

Text Solution

Verified by Experts

The correct Answer is:
b
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