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A stationary body of mass 3 kg explodes ...

A stationary body of mass 3 kg explodes into three equal pieces. Two of the pieces fly off in two mutually perpendicular directions, one with a velocity of `3hati ms^(1)` and the other with a velocity of `4hatj ms^(-1)` . - If the explosion occurs in `10^(–4) s`, the average force acting on the third piece in newton is

A

`(3hati+4hatj)xx10^(-4)`

B

`(3hati-4hatj)xx10^(-4)`

C

`(3hati+4hatj)xx10^(4)`

D

`-(3hati+4hatj)xx10^(4)`

Text Solution

Verified by Experts

The correct Answer is:
D
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