If tan.(B-C)/(2)=xcot.(A)/(2), then x =...

If `tan.(B-C)/(2)=xcot.(A)/(2)`, then x =

A

`(c-a)/(c+a)`

B

`(a-b)/(a+b)`

C

`(b-c)/(b+c)`

D

`(b-c)/(a)`

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The correct Answer is:

C

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