In DeltaABC,cot.(A+B)/(2).tan.(A-B)/(2)=...

In `DeltaABC,cot.(A+B)/(2).tan.(A-B)/(2)`=

A

`(a+b)/(a-b)`

B

`(a-b)/(a+b)`

C

`(a)/(a+b)`

D

`(b)/(a+b)`

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The correct Answer is:

B

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