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In DeltaABC,1-tan.(A)/(2)tan.(B)/(2)=...

In `DeltaABC,1-tan.(A)/(2)tan.(B)/(2)=`

A

(a) ` (2c)/(a+b+c)`

B

(b) `(a)/(a+b+c)`

C

(c) `(2)/(a+b+c)`

D

(d) `(4a)/(a+b+c)`

Text Solution

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The correct Answer is:
A
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