y=tan^(-1)((3a^2x-x^3)/(a(a^2-3x^2)))...

`y=tan^(-1)((3a^2x-x^3)/(a(a^2-3x^2)))`

A

(a) `3tan^(-1).(x)/(a)`

B

(b) `2tan^(-1).(x)/(a)`

C

(c) `tan^(-1).(x)/(a)`

D

(d) `tan^(-1).(a)/(x)`

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The correct Answer is:

A

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