In triangleABC, (cos2A)/(a^(2))-(cos2B)/...

In `triangleABC, (cos2A)/(a^(2))-(cos2B)/(b^(2))=`

A

(a) `a^(2)-b^(2)`

B

(b) `(1)/(a^(2)-b^(2))`

C

(c) `(1)/(a^(2))-(1)/(b^(2))`

D

(d) `a^(2)+b^(2)`

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The correct Answer is:

C

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