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In any DeltaABC under usual notation, a(...

In any `DeltaABC` under usual notation, `a(bcosC-c cosB)`=

A

(a) `b^(2)-c^(2)`

B

(b) `c^(2)-b^(2)`

C

(c) `(b^(2)-c^(2))/(2)`

D

(d) `(c^(2)-b^(2))/(2)`

Text Solution

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The correct Answer is:
A
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