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In a triangle ABC, if b^2 + c^2 = 3a^2, ...

In a `triangle ABC`, if `b^2 + c^2 = 3a^2`, then `cotB + cotC-cotA` is equal to

A

(a) 1

B

(b) `(ab)/(4Delta)`

C

(c) 0

D

(d) `(ac)/(4Delta)`

Text Solution

Verified by Experts

The correct Answer is:
C
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