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In DeltaABC,cosecA(sinBcosC+cosBsinC)=...

In `DeltaABC,cosecA(sinBcosC+cosBsinC)=`

A

(a) `c//a`

B

(b) `a//c`

C

(c) 1

D

(d) `c//ab`

Text Solution

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The correct Answer is:
C
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