In DeltaABC,tan.(A)/(2)+tan.(B)/(2)=...

In `DeltaABC,tan.(A)/(2)+tan.(B)/(2)`=

A

(a) `(c cot.(C)/(2))/(4s)`

B

(b) `(2c cot.(C)/(2))/(a+b+c)`

C

(c) `(2ctan.(C)/(2))/(s)`

D

(d) `(ctan.(C)/(2))/(a+b+c)`

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The correct Answer is:

B

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