If ax^(2)-y^(2)+4x-y=0 represents a pair...

If `ax^(2)-y^(2)+4x-y=0` represents a pair off lines then `a=`

A

(a) `-16`

B

(b) `16`

C

(c) `4`

D

(d) `-4`

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The correct Answer is:

B

NA

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