Home
Class 12
MATHS
The shortest distance between lines ba...

The shortest distance between lines
`barr=(lambda-1)hati+(lambda+1)hatj-(1+lambda)hatk` and
`barr=(1-mu)hati+(2mu-1)hatj+(mu+2)hatk` is

A

(a) `(sqrt(5))/(2)`

B

(b) `(5)/(sqrt(2))`

C

(c) `15`

D

(d) `5sqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The shortest distance between lines barr=(hati-hatj)+lambda(2hati+hatk)andbarr=(2hati-hatj)+mu(hati-hatj-hatk) is

The shortest distance between the lines barr=(4hati-hatj)+lambda(hati+2hatj-3hatk)andbarr=(hati-hatj+2hatk)+mu(2hati+4hatj-5hatk) is

Find the shortest distance between the following pair of line: vecr=(1-t)hati+(t-2)hatj+(3-2t)hatk and vecr=(s+1)hati+(2s-1)hatj-(2s+1)hatk.

Angle between lines barr=(hati+2hatj-hatk)+lambda(3hati-4hatk) and barr=(1-t)(4hati-hatj)+t(2hati+hatj-3hatk) is

The acute angle between the line barr=(3hati-hatj-hatk)+lambda(hati-hatj+hatk) and the plane barr.(3hati-4hatk)=4 is

The angle between the line barr=(2hati+3hatj+hatk)+lambda(hati+2hatj-hatk) and the plane barr.(2hati-hatj+hatk)=4 is

Cosine of the angle between the lines barr=5hati-hatj+4hatk+lambda(hati+2hatj+2hatk) and barr=7hati+2hatj+2hatk+mu(3hati+2hatj+6hatk) is

The cartesian equation of the line barr = (hati + hatj + hatk)+ lambda(hatj + hatk) is

If the angle between the planes bar r .(m hati -hatj+2hatk)+3=0 and bar r.(2hati -m hatj - hatk )-5=0 is (pi)/(3) , then m=

The equation of the plane containing lines barr=hati+2hatj-hatk+lambda(hati+2hatj-hatk) and barr=hati+2hatj-hatk+mu(hati+hatj+3hatk) is