int(log(logx))/(x.logx)dx=...

`int(log(logx))/(x.logx)dx=`

A

(a) `[log(logx)]^(2)+c`

B

(b) `1/2[log(logx)]^(2)+c`

C

(c) `log(logx)+c`

D

(d) `xlog(logx)+c`

Verified by Experts

The correct Answer is:

B

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int(logx)/((logex)^(2))*dx=

A

`(x)/(1+logx)+c`

B

`x(1+logx)+c`

C

`(1)/(1+logx)+c`

D

`(1)/(1-logx)+c`

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