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int(cos2x-cos2alpha)/(cosx-cosalpha)dx...

`int(cos2x-cos2alpha)/(cosx-cosalpha)dx`

A

(a) `2(sinx+xcosalpha)+c`

B

(b) `2(sinx+sinalpha)+c`

C

(c) `2(-sinx+xcosalpha)+c`

D

(d) `-2(sinx+sinalpha)+c`

Text Solution

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The correct Answer is:
A
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