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int(tanx)/(secx+tanx)dx=...

`int(tanx)/(secx+tanx)dx=`

A

(a) `secx+tanx-x+c`

B

(b) `secx-tanx+x+c`

C

(c) `secx+tanx+x+c`

D

(d) `-secx-tanx+x+c`

Text Solution

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The correct Answer is:
B
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