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int(sinx/(sin(x-alpha)))dx=...

`int(sinx/(sin(x-alpha)))dx`=

A

(a) `xsinalpha-sinalphalogabs(sin(x+alpha))+c`

B

(b) `xcosalpha+sinalphalogabs(sin(x-alpha))+c`

C

(c) `xcosalpha-sinalphalogabs(sin(x+alpha))+c`

D

(d) `xsinalpha+sinalphalogabs(sin(x-alpha))+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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