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int(cos(x+alpha))/cosx dx=...

`int(cos(x+alpha))/cosx dx=`

A

`(cosalpha)x-sinalphalogabs(cosx)+c`

B

`(cosalpha)x-sinalphalogabs(secx)+c`

C

`(cosalpha)x+sinalphalogabs(secx)+c`

D

`(cosalpha)+sinalphalogabs(cosx)+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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Knowledge Check

  • int(cos2x-1)/(cos2x+1)*dx=

    A
    `tanx-x+c`
    B
    `x+tanx+c`
    C
    `x-tanx+c`
    D
    `-x-cot x+c`
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