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int(dx)/(4cos^(3)2x-3cos2x)=...

`int(dx)/(4cos^(3)2x-3cos2x)=`

A

(a) `1/3logabs(sec6x+tan6x)+c`

B

(b) `1/6logabs(sec6x+tan6x)+c`

C

(c) `logabs(sec6x+tan6x)+c`

D

(d) `3logabs(sec6x+tan6x)+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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