intsec^(3)theta"d"theta=...

`intsec^(3)theta"d"theta=`

A

(a) `1/2(secthetatantheta+logabs(sectheta+tantheta))+c`

B

(b) `1/2(sectheta+tantheta+logabs(sectheta+tantheta))+c`

C

(c) `1/4(secthetatantheta+logabs(secthetatantheta))+c`

D

(d) `secthetatantheta+logabs(secthetatantheta)+c`

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The correct Answer is:

A

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