int(dx)/(e^(x)+1-2e^(-x))=...

`int(dx)/(e^(x)+1-2e^(-x))=`

A

(a) `logabs(e^(x)-1)-logabs(e^(x)+2)+c`

B

(b) `1/2logabs(e^(x)-1)-1/3logabs(e^(x)+2)+c`

C

(c) `1/3logabs(e^(x)-1)-1/3logabs(e^(x)+2)+c`

D

(d) `1/3logabs(e^(x)-1)+1/3logabs(e^(x)+2)+c`

Verified by Experts

The correct Answer is:

C

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