intcosx/((1+sinx)(2+sinx))dx...

`intcosx/((1+sinx)(2+sinx))dx`

A

(a) `logabs((1+sinx)(2+sinx))+c`

B

(b) `logabs((2+sinx)/(1+sinx))+c`

C

(c) `logabs((1+sinx)/(2+sinx))+c`

D

(d) `logabs((2+cosx)/(1+sinx))+c`

Verified by Experts

The correct Answer is:

C

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