If A=[{:(a,0,0),(0,b,0),(0,0,c):}], a=7^...

If `A=[{:(a,0,0),(0,b,0),(0,0,c):}], a=7^(x), b=7^(7^(x)), c=7^(7^(7^(x)))`, then `intabs(A)dx`,
where `abs(A)` is the determinant of the matrix `A`, equals

A

(a) `7^(7^(x))/(log7)^(3)+c`

B

(b) `7^(7^(7^(x)))/(log7)+c`

C

(c) `7^(7^(7^(x))).(log7)^(3)+c`

D

(d) `(7^(7^(7^(x))))/(log7)^(3)+c`

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The correct Answer is:

D

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