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int(cos2x-cos2alpha)/(cosx-cosalpha)dx=...

`int(cos2x-cos2alpha)/(cosx-cosalpha)dx=`

A

`2(sinx+xcostheta)+c`

B

`2(sinx-xcosthet)+c`

C

`2(sinx+2xcostheta)+c`

D

`2(sinx-2xcostheta)+c`

Text Solution

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The correct Answer is:
A
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