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If int (sin2x-cos2x)dx=1/sqrt2sin(2x-a)+...

If `int (sin2x-cos2x)dx=1/sqrt2sin(2x-a)+b` then

A

`a=pi/4, b=0`

B

`a=-pi/4, b=0`

C

`a=(5pi)/4,` b= any constant

D

`a=-(5pi)/4,` b=any constant

Text Solution

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The correct Answer is:
D
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