`intsec^(5)xtanxdx=?`

A

`1/5sec^(5)x+c`

B

`4sec^(4)x+c`

C

`(sec^(3))/3+c`

D

`3sec^(3)x+c`

Verified by Experts

The correct Answer is:

A

Similar Questions

Explore conceptually related problems

intsec^6xdx=

intsec^(3)theta"d"theta=

Evaluate the following: intsec^2x/(2tan^2x+7tanx+13)dx

For n ge 2, " if " I_(n)=intsec^(n)xdx, " then " I_(4)-2/3I_(2)=

intsec^(25//13)xcosec^(27//13)xdx=

intsec^(2/3)xcosec^(4/3)xdx=

Evaluate intsec^(2)x"cosec"^(2)xdx .

int_- 5^5|x+2|dx