inte^(sinx)(xcosx-secxtanx)dx=""+c, 0 lt...

`inte^(sinx)(xcosx-secxtanx)dx="______"+c, 0 lt x lt pi/2`

A

(a) `e^(sinx)(x-secx)`

B

(b) `e^(sinx)(secx-x)`

C

(c) `e^(sinx)xcosx`

D

(d) `e^(sinx)(x+secx)`

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The correct Answer is:

A

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