The integral intcos(log(e)x)dx is equal ...

The integral `intcos(log_(e)x)dx` is equal to:
(where C is a constant of integration)

A

(a) `1/2x[cos(log_(e)x)+sin(log_(e)x)]+c`

B

(b) `x[cos(log_(e)x)+sin(log_(e)x)]+c`

C

(c) `1/2x[cos(log_(e)x)-sin(log_(e)x)]+c`

D

(d) `x[cos(log_(e)x)-sin(log_(e)x)]+c`

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The correct Answer is:

A

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