inte^(sinx)((sinx+1)/(secx))dx is equal ...

`inte^(sinx)((sinx+1)/(secx))dx` is equal to

A

`sinx.e^(sinx)+c`

B

`cosx.e^(sinx)+c`

C

`e^(sinx)+c`

D

`e^(sinx)(sinx+1)+c`

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The correct Answer is:

A

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