If intf(x)/(logcosx)dx=-log(logcosx)+c, ...

If `intf(x)/(logcosx)dx=-log(logcosx)+c`, then f(x) is equal to

A

(a) `tanx`

B

(b) `-sinx`

C

(c) `-cosx`

D

(d) `-tanx`

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The correct Answer is:

A

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