If int1/((x^(2)-1))log((x-1)/(x+1))dx=A[...

If `int1/((x^(2)-1))log((x-1)/(x+1))dx=A[log((x-1)/(x+1))]^(2)+c`, then A =

A

(a) `1/2`

B

(b) `1/3`

C

(c) `1/4`

D

(d) `1/6`

Verified by Experts

The correct Answer is:

C

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