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intsec^(25//13)xcosec^(27//13)xdx=...

`intsec^(25//13)xcosec^(27//13)xdx=`

A

(a) `-15/13(tanx)^(-15//13)+3/12(tanx)^(3//2)+c`

B

(b) `-13/14(tanx)^(-14//13)+13/12(tanx)^(12//13)+c`

C

(c) `-14/13(tanx)^(-13//14)+2/3(tanx)^(3//2)+c`

D

(d) None of these

Text Solution

Verified by Experts

The correct Answer is:
B
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