If u =-f''(theta) sintheta + f'(theta) c...

If `u =-f''(theta) sintheta + f'(theta) costheta` and
`v = f''(theta) costheta + f'(theta) sintheta`,
then `int[((du)/(d theta))^2+((dv)/(d theta))^2]^(1/2)d theta` is equal to

A

(a) `f(theta)-f''(theta)+c`

B

(b) `f(theta)+f''(theta)+c`

C

(c) `f'(theta)+f''(theta)+c`

D

(d) `f'(theta)-f''(theta)+c`

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The correct Answer is:

B

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