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The outer electronic configuration of th...

The outer electronic configuration of the element No (Nobelium, Z = 102) is____________.

A

`5f^(14) 6d^0 7s^2`

B

`5f^(13) 6d^1 7s^2`

C

`5f^(14) 6d^1 7s^1`

D

`5f^(14) 6d^0 7s^1`

Text Solution

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The correct Answer is:
A
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