Home
Class 12
MATHS
The equation to the perpendicular from t...

The equation to the perpendicular from the point `(alpha, beta, gamma)` to
the plane `ax+by+cz+d=0` is

A

(a) `a(x-alpha)+b(y-beta)+c(z-gamma)=0`

B

(b) `(x-alpha)/(a)=(y-beta)/(b)=(z-gamma)/(c)`

C

(c) `a(x-alpha)+b(y-beta)+c(z-gamma)=abc`

D

(d) `(x-a)/(alpha)=(y-b)/(beta)=(z-c)/(gamma)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

The foot of the perpendicular from the point (alpha,beta,gamma) on Y-axis is

The equation of the plane passing through (alpha,beta, gamma) and parallel to ax+by+cz=0 is

Square of the length of the tangent drawn from the point (alpha,beta) to the circle ax^2 +ay^2=r^2 is

If alpha+beta+gamma=2pi then

The perpendicular distance of the point P(6,7,8) from xy-plane is

Derive the relation between alpha , beta , and gamma for a solid.

If the foot of the perpendicular from O(0,0,0) to a plane is P(1,2,2) . Then the equation of the plane is