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The direction cosines of the normal to t...

The direction cosines of the normal to the plane
`x + 2y - 3z + 4 = 0` are

A

`-(1)/(sqrt(14)),-(2)/(sqrt(14)),-(-3)/(sqrt(14))`

B

`(1)/(sqrt(14)),(2)/(sqrt(14)),(3)/(sqrt(14))`

C

`-(1)/(sqrt(14)),(2)/(sqrt(14)),(3)/(sqrt(14))`

D

`(1)/(sqrt(14)),(2)/(sqrt(14)),-(3)/(sqrt(14))`

Text Solution

Verified by Experts

The correct Answer is:
D
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