Home
Class 12
MATHS
The equation of the plane through (1, 2,...

The equation of the plane through `(1, 2,-3)` and `(2, -2, 1)` and parallel to `X`-axis is

A

y-z+1=0

B

y-z-1=0

C

y+z-1=0

D

y+z+1=0

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

Equation of the plane passing through points (1,-1,3) and (2,3,-4) and parallel to X-axis is

The equation of the plane through the point (2,-1,-3) and parallel to the lines (x-1)/(3)=(y+2)/(2)=(z)/(-4) and (x)/(2)=(y-1)/(-3)=(z-2)/(2) is

The equation of the plane through (2,3,4) and parallel to the plane x+ 2y + 4z =25 is :

The equation of the plane through the points (2,-1,0) , (3,-4,5) parallel to a line with direction cosines proportional to 2,3,4 is 9x-2y-3z=k , where k is

The equation of the plane passing through (1,1,1) and (1,-1,-1) and perpendicular to 2x-y+z+5=0 is

Equation of the plane passing through (-1,3,4) and parallel to YZ-plane is

The equation of the plane passing through (2,3,4) and parallel to the plane 5x-6y+7z=3 is

The vector equation of the line passing through (2,3,4) and parallel to Z-axis is

The vector equation of the line passing through (2, 1, -1) and parallel to hati+2hatj+hatk is