Home
Class 12
MATHS
The equation of the plane passing throug...

The equation of the plane passing through the points `(0,1,2)` and `(-1,0,3)` and
perpendicular to the plane `2x+3y+z=5` is

A

3x-4y+18z+32=0

B

3x+4y-18z+32=0

C

4x+3y-17z+31=0

D

4x-3y+z+1=0

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the plane passing through the points (1,2,3), (-1,4,2) and (3,1,1) is

The equation of the plane passing through the point (1, -3, -2) and perpendicular to the planes x+2y+2z=5 and 3x+3y+2z=8 is -

The equation of the line passing though the point (1,1,-1) and perpendicular to the plane x -2y - 3z =7 is :

The equation of the plane passing through (1,1,1) and (1,-1,-1) and perpendicular to 2x-y+z+5=0 is

The equation of the line passing through the point (1,2) and perpendicular to the line x+y+1=0 is

The equation of the plane that passes through the points (1,0,2), (-1,1,2), (5,0,3) is

The equation of the plane passing through the point (-10,5,4) and perpendicular to the line joining the points (4,-1,2) and (-3,2,3) is

Equation of the plane passing through points (1,-1,3) and (2,3,-4) and parallel to X-axis is

The equation of a line passing through point (1,2,3) and perpendicular to the plane x+2y-5z+9=0 are