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A plane is at a distance of 5 units form...

A plane is at a distance of `5` units form the origin and perpendicular to the vector
`2hati+hatj+2hatk`. The equation of the plane is

A

`barr.(2hati+hatj-2hatk)=15`

B

`barr.(2hati+hatj-hatk)=15`

C

`barr.(2hati+hatj+2hatk)=15`

D

`barr.(hati+hatj+2hatk)=15`

Text Solution

Verified by Experts

The correct Answer is:
C
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