If the distance of the point P(1,-2,1)...

If the distance of the point `P(1,-2,1)` from the plane `x+2y-2z=alpha`, where `alpha>0`, is `5,`
then the foot of the perpendicular from `P` to the place is

A

`((8)/(3),(4)/(3),(-7)/(3))`

B

`((4)/(3),(-4)/(3),(1)/(3))`

C

`((1)/(3),(2)/(3),(10)/(3))`

D

`((2)/(3),-(1)/(3),(5)/(2))`

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The correct Answer is:

A

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